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The reactive electrophile in the Reimer–Tiemann reaction is
A$Cl^-$
B$OH^-$
CDichlorocarbene $:CCl_2$
D$CHCl_3$ itself
Answer & Solution
Correct answer: C. Dichlorocarbene $:CCl_2$
$CHCl_3 + OH^- \to :CCl_2 + Cl^- + H_2O$. The carbene attacks the ortho carbon of phenoxide. Subsequent hydrolysis of the geminal dichloride gives $-CHO$.
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