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The reaction of $CH_3MgBr$ with formaldehyde ($HCHO$), followed by acidic workup, gives
A1-Propanol
BAcetone
CMethanol
DEthanol
Answer & Solution
Correct answer: D. Ethanol
Grignards add to $C=O$. $HCHO + CH_3MgBr \to CH_3CH_2OMgBr \xrightarrow{H_3O^+} CH_3CH_2OH$. Formaldehyde + any Grignard gives a 1° alcohol with one extra carbon.
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