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Karnataka SSLC (Class 10) Arithmetic Progression — practice questions — page 3

Explore 126 free Arithmetic Progression questions in Karnataka SSLC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Arithmetic Progression questions and exercises with answers

Showing questions 61–90 of 126.

Find the midpoint of A(2, −3) and B(8, 5).Read the answer and worked solution →Find the point P that divides the segment joining A(1, 2) and B(7, 8) in the ratio 1 : 2.Read the answer and worked solution →The midpoint of segment AB is (4, 5). If A = (2, 3), what is B?Read the answer and worked solution →Find the point dividing the segment joining (4, −1) and (−2, −3) in the ratio 1 : 3.Read the answer and worked solution →The centroid of a triangle with vertices A(1, 1), B(4, 7), C(7, 1) is:Read the answer and worked solution →The nth term of an AP with first term a and common difference d is:Read the answer and worked solution →Sum of the first n terms of an AP is:Read the answer and worked solution →CLASS10 · Mathematics · Arithmetic ProgressionRead the answer and worked solution →A list of numbers in which each term is obtained by adding a fixed number to the preceding term is calledRead the answer and worked solution →For an AP with first term $a$ and common difference $d$, the general form isRead the answer and worked solution →The common difference of the AP $3,\ 7,\ 11,\ 15,\ \ldots$ isRead the answer and worked solution →The formula for the $n$th term of an AP with first term $a$ and common difference $d$ isRead the answer and worked solution →For the AP $5,\ 5,\ 5,\ 5,\ \ldots$ the common difference isRead the answer and worked solution →The 10th term of the AP $2,\ 7,\ 12,\ 17,\ \ldots$ isRead the answer and worked solution →Which term of the AP $3,\ 8,\ 13,\ 18,\ \ldots$ is equal to $78$?Read the answer and worked solution →The sum of the first $n$ terms of an AP is given byRead the answer and worked solution →The sum of the first 20 terms of the AP $1,\ 3,\ 5,\ 7,\ \ldots$ isRead the answer and worked solution →If the first term of an AP is 6 and the common difference is $-3$, the AP isRead the answer and worked solution →How many terms are there in the finite AP $7,\ 13,\ 19,\ \ldots,\ 205$?Read the answer and worked solution →The common difference of an AP whose $n$th term is $a_n = 3n + 2$ isRead the answer and worked solution →The sum of the first $n$ natural numbers $1 + 2 + 3 + \cdots + n$ equalsRead the answer and worked solution →In an AP, the 3rd term is 12 and the 7th term is 24. The first term $a$ and common difference $d$ areRead the answer and worked solution →If the sum of the first $n$ terms of a sequence is $S_n = n^2$, its $n$th term $a_n$ isRead the answer and worked solution →A man's starting salary is ₹8000 with an annual increment of ₹500. His salary in the 6th year isRead the answer and worked solution →The sum $2 + 4 + 6 + \cdots + 100$ (the first 50 even numbers) isRead the answer and worked solution →For the AP $10,\ 7,\ 4,\ \ldots$, the term that first becomes negative is theRead the answer and worked solution →The distance between two points $P(x_1,y_1)$ and $Q(x_2,y_2)$ isRead the answer and worked solution →The distance of a point $P(x,y)$ from the origin isRead the answer and worked solution →The mid-point of the line segment joining $(x_1,y_1)$ and $(x_2,y_2)$ isRead the answer and worked solution →The distance between the points $(0,0)$ and $(3,4)$ isRead the answer and worked solution →

Worked practice questions

Find the midpoint of A(2, −3) and B(8, 5).

  1. (6, 1)
  2. (5, 1)
  3. (5, 2)
  4. (10, 2)
Show answer and solution

Correct answer: B. (5, 1)

((2 + 8)/2, (−3 + 5)/2) = (10/2, 2/2) = (5, 1).

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Find the point P that divides the segment joining A(1, 2) and B(7, 8) in the ratio 1 : 2.

  1. (3, 4)
  2. (2, 4)
  3. (4, 5)
  4. (5, 6)
Show answer and solution

Correct answer: A. (3, 4)

P = ((1·7 + 2·1)/3, (1·8 + 2·2)/3) = (9/3, 12/3) = (3, 4).

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The midpoint of segment AB is (4, 5). If A = (2, 3), what is B?

  1. (6, 8)
  2. (6, 7)
  3. (3, 4)
  4. (8, 7)
Show answer and solution

Correct answer: B. (6, 7)

(A + B)/2 = (4, 5) ⇒ B = 2·(4, 5) − A = (8, 10) − (2, 3) = (6, 7).

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