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If the first term of an AP is 6 and the common difference is $-3$, the AP is
A$6,\ 9,\ 12,\ 15,\ \ldots$
B$6,\ -3,\ -12,\ \ldots$
C$6,\ 2,\ -2,\ \ldots$
D$6,\ 3,\ 0,\ -3,\ \ldots$
Answer & Solution
Correct answer: D. $6,\ 3,\ 0,\ -3,\ \ldots$
1. Start at a = 6 and add d = −3 each time.
2. 6, 6+(−3)=3, 3+(−3)=0, 0+(−3)=−3, …
3. So the AP is 6, 3, 0, −3, …
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch1 'Arithmetic Progressions' (listing an AP)_
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