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Karnataka SSLC (Class 10) Introduction to Trigonometry — practice questions

Explore 12 free Introduction to Trigonometry questions in Karnataka SSLC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Introduction to Trigonometry questions and exercises with answers

Showing questions 1–12 of 12.

For an acute angle $A$ in a right triangle, $\sin A$ equalsRead the answer and worked solution →$\cos A$ for an acute angle $A$ is defined asRead the answer and worked solution →The value of $\tan 45^\circ$ isRead the answer and worked solution →The reciprocal of $\sin A$ isRead the answer and worked solution →The value of $\sin 30^\circ$ isRead the answer and worked solution →The fundamental identity relating $\sin A$ and $\cos A$ isRead the answer and worked solution →The identity $1 + \tan^2 A$ equalsRead the answer and worked solution →Using complementary angles, $\sin(90^\circ - A)$ equalsRead the answer and worked solution →The value of $\cos 0^\circ$ isRead the answer and worked solution →If $\tan A = 1$, then the acute angle $A$ isRead the answer and worked solution →The value of $\sin^2 30^\circ + \cos^2 30^\circ$ isRead the answer and worked solution →Fill in the four trig valuesRead the answer and worked solution →

Worked practice questions

For an acute angle $A$ in a right triangle, $\sin A$ equals

  1. $\dfrac{\text{opposite}}{\text{hypotenuse}}$
  2. $\dfrac{\text{adjacent}}{\text{hypotenuse}}$
  3. $\dfrac{\text{opposite}}{\text{adjacent}}$
  4. $\dfrac{\text{hypotenuse}}{\text{opposite}}$
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Correct answer: A. $\dfrac{\text{opposite}}{\text{hypotenuse}}$

1. $\sin A$ is the ratio of the side opposite A to the hypotenuse. 2. $\sin A = \dfrac{\text{opposite}}{\text{hypotenuse}}$. 3. (cos A uses the adjacent side; tan A = opposite/adjacent.) _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch11 'Introduction to Trigonometry', §11.1_

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$\cos A$ for an acute angle $A$ is defined as

  1. $\dfrac{\text{opposite}}{\text{hypotenuse}}$
  2. $\dfrac{\text{adjacent}}{\text{hypotenuse}}$
  3. $\dfrac{\text{adjacent}}{\text{opposite}}$
  4. $\dfrac{\text{hypotenuse}}{\text{adjacent}}$
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Correct answer: B. $\dfrac{\text{adjacent}}{\text{hypotenuse}}$

1. $\cos A$ is the ratio of the adjacent side to the hypotenuse. 2. $\cos A = \dfrac{\text{adjacent}}{\text{hypotenuse}}$. 3. Its reciprocal is $\sec A$. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch11 'Introduction to Trigonometry', §11.1_

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The value of $\tan 45^\circ$ is

  1. 0
  2. $\dfrac{1}{2}$
  3. 1
  4. $\sqrt{3}$
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Correct answer: C. 1

1. At $45^\circ$ the opposite and adjacent sides are equal. 2. So $\tan 45^\circ = \dfrac{\text{opposite}}{\text{adjacent}} = 1$. 3. Hence $\tan 45^\circ = 1$. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch11 'Introduction to Trigonometry', §11.2 (standard angles)_

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