Start learning →

The nth term of an AP with first term a and common difference d is:

Aa + (n − 1) d
Ba + n d
C2a + n d
Dn d
Answer & Solution
Correct answer: A. a + (n − 1) d
An Arithmetic Progression (AP) is a sequence of numbers where the difference between consecutive terms is constant. This constant is called the common difference, denoted by $d$. Let the terms of the AP be $T_1, T_2, T_3, \dots, T_n$. 1. **First term ($T_1$):** By definition, $T_1 = a$. 2. **Second term ($T_2$):** We add the common difference once to the first term: $T_2 = a + d$. 3. **Third term ($T_3$):** We add $d$ to the second term: $T_3 = (a + d) + d = a + 2d$. 4. **Fourth term ($T_4$):** Similarly, $T_4 = a + 3d$. **Observation:** Notice the relationship between the term number ($n$) and the coefficient of $d$: - For $n=1$, coefficient is $0$ ($1-1$) - For $n=2$, coefficient is $1$ ($2-1$) - For $n=3$, coefficient is $2$ ($3-1$) Following this pattern, for the **$n$-th term ($T_n$)**, the common difference $d$ is added $(n-1)$ times to the first term $a$. Thus, the formula is: $$T_n = a + (n - 1)d$$
Practise this question with Quill — CBSE Class 10 →

Keep practising Arithmetic Progressions

Browse all Arithmetic Progressions questions for CBSE Class 10, or explore more Mathematics topics.

Start a Arithmetic Progressions lesson →