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Karnataka SSLC (Class 10) Arithmetic Progression — practice questions — page 4

Explore 126 free Arithmetic Progression questions in Karnataka SSLC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Arithmetic Progression questions and exercises with answers

Showing questions 91–120 of 126.

The distance between the points $(1,2)$ and $(4,6)$ isRead the answer and worked solution →The mid-point of the segment joining $(2,3)$ and $(4,7)$ isRead the answer and worked solution →The distance of the point $(5,12)$ from the origin isRead the answer and worked solution →The point that divides the segment joining $(1,2)$ and $(3,4)$ in the ratio $1:1$ isRead the answer and worked solution →The area of the triangle with vertices $(0,0)$, $(4,0)$ and $(0,3)$ isRead the answer and worked solution →Three points are collinear if the area of the triangle formed by them isRead the answer and worked solution →The distance between the points $(2,3)$ and $(2,8)$ isRead the answer and worked solution →A point that lies on the x-axis has itsRead the answer and worked solution →Complete the definition of conditional probabilityRead the answer and worked solution →True or false: conditional probabilityRead the answer and worked solution →Independent or mutually exclusive?Read the answer and worked solution →Match each rule to its nameRead the answer and worked solution →IndependenceRead the answer and worked solution →Order the steps for a Bayes' theorem questionRead the answer and worked solution →Complete the conditions for a partitionRead the answer and worked solution →True or false: independence versus exclusivityRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Tap every statement that follows from independenceRead the answer and worked solution →The multiplication ruleRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Complete the theorem of total probabilityRead the answer and worked solution →Which theorem answers which question?Read the answer and worked solution →True or false: total probability and BayesRead the answer and worked solution →Match each historical figure to their contributionRead the answer and worked solution →The Historical NoteRead the answer and worked solution →Flip and pair: notation with meaningRead the answer and worked solution →Order the reasoning: from a partition to a posteriorRead the answer and worked solution →Tap every quantity that is a probabilityRead the answer and worked solution →

Worked practice questions

The distance between the points $(1,2)$ and $(4,6)$ is

  1. 6
  2. 7
  3. 5
  4. 4
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Correct answer: C. 5

1. Distance $=\sqrt{(4-1)^2+(6-2)^2}=\sqrt{3^2+4^2}$. 2. $=\sqrt{9+16}=\sqrt{25}=5$. 3. So the distance is 5 units. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.2_

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The mid-point of the segment joining $(2,3)$ and $(4,7)$ is

  1. $(6,10)$
  2. $(1,2)$
  3. $(2,4)$
  4. $(3,5)$
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Correct answer: D. $(3,5)$

1. Mid-point $=\left(\dfrac{2+4}{2},\ \dfrac{3+7}{2}\right)$. 2. $=\left(\dfrac{6}{2},\ \dfrac{10}{2}\right)=(3,5)$. 3. So the mid-point is $(3,5)$. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.3_

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The distance of the point $(5,12)$ from the origin is

  1. 13
  2. 17
  3. 7
  4. 60
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Correct answer: A. 13

1. Distance from origin $=\sqrt{5^2+12^2}=\sqrt{25+144}$. 2. $=\sqrt{169}=13$. 3. So the distance is 13 units. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.2_

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