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The mid-point of the line segment joining $(x_1,y_1)$ and $(x_2,y_2)$ is
A$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$
B$\left(x_1+x_2,\ y_1+y_2\right)$
C$\left(\dfrac{x_1-x_2}{2},\ \dfrac{y_1-y_2}{2}\right)$
D$\left(x_1 x_2,\ y_1 y_2\right)$
Answer & Solution
Correct answer: A. $\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$
1. The mid-point divides the segment in the ratio 1:1.
2. Its coordinates are the averages: $\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$.
3. This is a special case of the section formula.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.3_
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