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The distance between the points $(0,0)$ and $(3,4)$ is
A7
B5
C12
D25
Answer & Solution
Correct answer: B. 5
1. Distance $=\sqrt{(3-0)^2+(4-0)^2}=\sqrt{9+16}$.
2. $=\sqrt{25}=5$.
3. So the distance is 5 units.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.2_
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