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The sum $2 + 4 + 6 + \cdots + 100$ (the first 50 even numbers) is
A2450
B2500
C2550
D5050
Answer & Solution
Correct answer: C. 2550
1. a = 2, d = 2, n = 50, last term l = 100.
2. $S_{50} = \tfrac{n}{2}(a + l) = \tfrac{50}{2}(2 + 100) = 25(102)$.
3. $S_{50} = 2550$.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch1 'Arithmetic Progressions' (sum, first term/last term form)_
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