The sum $2 + 4 + 6 + \cdots + 100$ (the first 50 even numbers) is
A2450
B2500
C2550
D5050
Answer & Solution
Correct answer: C. 2550
1. a = 2, d = 2, n = 50, last term l = 100.
2. $S_{50} = \tfrac{n}{2}(a + l) = \tfrac{50}{2}(2 + 100) = 25(102)$.
3. $S_{50} = 2550$.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch1 'Arithmetic Progressions' (sum, first term/last term form)_
Keep practising Arithmetic Progressions
Browse all Arithmetic Progressions questions for Karnataka SSLC (Class 10), or explore more Mathematics topics.
Related questions
Key in the AP answerMatch each AP termFor the AP $10,\ 7,\ 4,\ \ldots$, the term that first becomes negative is theA man's starting salary is ₹8000 with an annual increment of ₹500. His salary in the 6th yIf the sum of the first $n$ terms of a sequence is $S_n = n^2$, its $n$th term $a_n$ isIn an AP, the 3rd term is 12 and the 7th term is 24. The first term $a$ and common differeThe sum of the first $n$ natural numbers $1 + 2 + 3 + \cdots + n$ equalsThe common difference of an AP whose $n$th term is $a_n = 3n + 2$ is