Start learning →

The sum $2 + 4 + 6 + \cdots + 100$ (the first 50 even numbers) is

A2450
B2500
C2550
D5050
Answer & Solution
Correct answer: C. 2550
1. a = 2, d = 2, n = 50, last term l = 100. 2. $S_{50} = \tfrac{n}{2}(a + l) = \tfrac{50}{2}(2 + 100) = 25(102)$. 3. $S_{50} = 2550$. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch1 'Arithmetic Progressions' (sum, first term/last term form)_
Practise this question with Quill — Karnataka SSLC (Class 10) →

Keep practising Arithmetic Progressions

Browse all Arithmetic Progressions questions for Karnataka SSLC (Class 10), or explore more Mathematics topics.

Start a Arithmetic Progressions lesson →
Related questions