alleryStart learning →A man's starting salary is ₹8000 with an annual increment of ₹500. His salary in the 6th year is
A₹10000
B₹10500
C₹11000
D₹9500
Answer & Solution
Correct answer: B. ₹10500
1. Salaries form an AP: a = 8000, d = 500.
2. 6th-year salary $= a_6 = a + 5d = 8000 + 5(500) = 8000 + 2500$.
3. $a_6 = ₹10500$.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch1 'Arithmetic Progressions' (worked example, salary pattern)_
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