Mean of measurements: x̄. Standard error of mean for n trials:
- σ²
- σ × n
- σ
- σ/sqrt(n) (standard error)
Show answer and solution
Correct answer: D. σ/sqrt(n) (standard error)
σ_mean = σ/sqrt(n).
Standard error decreases as 1/sqrt(n) with more trials.
Hence averaging helps reduce random noise.
To improve precision 10×, need 100× more measurements.