alleryPhoton of wavelength 200 nm strikes metal with work function 2 eV. KE of fastest photoelectron (hc = 1240 eV nm):
A4.2 eV (= 6.2 - 2)
B2 eV
C6.2 eV
D1240 eV
Answer & Solution
Correct answer: A. 4.2 eV (= 6.2 - 2)
E_photon = 1240/200 = 6.2 eV.
We have KE_max = E - W.
That is KE_max = 6.2 - 2.
So KE_max = 4.2 eV.
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