A particle moves in a straight line with velocity v = 4t - t² m/s. The displacement of the particle in the time interval from t = 0 to when v becomes zero again is:
A16 m
B8 m
C32/3 m
D16/3 m
Answer & Solution
Correct answer: C. 32/3 m
v = 0 at t = 0 and t = 4. Displacement = ∫₀⁴ (4t - t²) dt = [2t² - t³/3]₀⁴ = 32 - 64/3 = 32/3 m.
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