alleryMean of measurements: x̄. Standard error of mean for n trials:
Aσ²
Bσ × n
Cσ
Dσ/sqrt(n) (standard error)
Answer & Solution
Correct answer: D. σ/sqrt(n) (standard error)
σ_mean = σ/sqrt(n).
Standard error decreases as 1/sqrt(n) with more trials.
Hence averaging helps reduce random noise.
To improve precision 10×, need 100× more measurements.
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