alleryFor a body in SHM with amplitude A, at displacement x, ratio of KE to total energy:
Ax²/A²
BA²/x²
Cx/A
D1 - x²/A²
Answer & Solution
Correct answer: D. 1 - x²/A²
Total E = (1/2)kA². PE at x = (1/2)kx².
KE = E - PE = (1/2)k(A² - x²). KE/E = 1 - x²/A².
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