alleryWork done in stretching wire by 1 mm is W. Work to stretch it by 2 mm (same wire, within elastic limit):
A8W
BW
C2W
D4W (W ∝ x², energy in spring/wire)
Answer & Solution
Correct answer: D. 4W (W ∝ x², energy in spring/wire)
Elastic energy = (1/2) k x².
Stretching x² gives 4× the work compared to x.
Same for stretching wire (Y stays same, F linear in x, work = ½ F x = ½ (Y A x/L) x ∝ x²).
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