Two particles of mass m and 4m have same kinetic energy. Ratio of their de Broglie wavelengths:
A1:1
B4:1
C1:2
D2:1
Answer & Solution
Correct answer: D. 2:1
λ = h/p = h/sqrt(2mKE). Same KE: λ ∝ 1/sqrt(m). λ₁/λ₂ = sqrt(m₂/m₁) = sqrt(4) = 2. Hence 2:1.
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