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JEE Main Unit 1C: Kinematics: Relative & Circular Motion — practice questions

Explore 59 free Unit 1C: Kinematics: Relative & Circular Motion questions in JEE Main Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 1C: Kinematics: Relative & Circular Motion questions and exercises with answers

Showing questions 1–30 of 59.

Two equal masses (3 kg each) connected by a light string over a frictionless pulley. One on smooth horizontal table, other hangs over edge. Acceleration?Read the answer and worked solution →A pendulum of mass m swings to amplitude angle θ. At the lowest point of swing, the TENSION in the string equals:Read the answer and worked solution →A car of mass 1000 kg moving at 36 km/h is stopped by brakes in 5 seconds. Average force exerted by brakes:Read the answer and worked solution →Escape velocity from a planet of mass M and radius R is v. From a planet of mass 4M and radius 2R, escape velocity:Read the answer and worked solution →At what height above Earth's surface is g reduced to half its surface value?Read the answer and worked solution →A body falls from infinity to Earth's surface. Its velocity at the surface (in terms of escape velocity v_e):Read the answer and worked solution →Two satellites of equal mass orbit Earth at radii r1 and r2 = 2r1. Ratio of their kinetic energies KE1 : KE2:Read the answer and worked solution →Gravitational potential at the centre of a uniform spherical shell of mass M and radius R:Read the answer and worked solution →A geostationary satellite orbits Earth at radius r_g. Another satellite orbits at radius r_g/4. Its period is approximately:Read the answer and worked solution →The acceleration due to gravity on Moon (mass 1/81 Earth, radius 1/4 Earth) is approximately:Read the answer and worked solution →Gravitational PE of a 2 kg mass at altitude 2R above Earth's surface (g at surface = 10, R = 6400 km):Read the answer and worked solution →At what point on the line joining Earth and Moon is the net gravitational field zero? (M_E = 81 M_moon)Read the answer and worked solution →Total mechanical energy of a satellite escaping Earth from low orbit at radius R is:Read the answer and worked solution →A particle moving back and forth over the same path is undergoing:Read the answer and worked solution →In SHM, the time for one complete oscillation is called:Read the answer and worked solution →The general equation for SHM is:Read the answer and worked solution →In SHM, displacement and acceleration are:Read the answer and worked solution →The angular frequency ω of a spring-mass system with mass m and spring constant k is:Read the answer and worked solution →Time period of a simple pendulum of length L (small oscillations):Read the answer and worked solution →A spring-mass system has mass 4 kg and spring constant 100 N/m. Frequency of SHM:Read the answer and worked solution →For SHM x = 5 sin(2πt), find amplitude and time period:Read the answer and worked solution →Maximum velocity of a particle in SHM with amplitude A and angular frequency ω:Read the answer and worked solution →Maximum acceleration of a particle in SHM (amplitude A, angular frequency ω):Read the answer and worked solution →A particle executing SHM has time period T. Time taken to go from extreme position (x = A) to x = A/2:Read the answer and worked solution →A simple pendulum of length 1 m has period T (g = 9.8). New length needed to double T:Read the answer and worked solution →Total energy of SHM particle equals:Read the answer and worked solution →At the extreme position in SHM, kinetic energy equals:Read the answer and worked solution →Two springs k1 and k2 in parallel: equivalent spring constant:Read the answer and worked solution →Two springs k1 and k2 in series: equivalent spring constant:Read the answer and worked solution →A spring of force constant k is cut into two equal halves. Spring constant of each half:Read the answer and worked solution →

Worked practice questions

Two equal masses (3 kg each) connected by a light string over a frictionless pulley. One on smooth horizontal table, other hangs over edge. Acceleration?

  1. g/2 = 5 m/s²
  2. g/4 = 2.5 m/s²
  3. g = 10 m/s²
  4. Zero
Show answer and solution

Correct answer: A. g/2 = 5 m/s²

**Hanging mass:** T = m(g - a). Mass on table: T = ma. **Equating:** m(g - a) = ma → g - a = a → a = g/2 = 5 m/s². (Atwood-like setup with no friction.)

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A pendulum of mass m swings to amplitude angle θ. At the lowest point of swing, the TENSION in the string equals:

  1. mg
  2. mg(2 − cos θ)
  3. mg(3 − 2cos θ)
  4. 2mg sin θ
Show answer and solution

Correct answer: C. mg(3 − 2cos θ)

**At the lowest point:** T − mg = mv²/L (centripetal). v² at bottom = 2gL(1 − cos θ) (energy conservation from amplitude). We have So T = mg + 2mg(1 − cos θ). So So T = mg(3 − 2cos θ). For θ = 60°: T = mg(3 − 1) = 2mg.

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A car of mass 1000 kg moving at 36 km/h is stopped by brakes in 5 seconds. Average force exerted by brakes:

  1. 1000 N
  2. 2000 N
  3. 5000 N
  4. 10000 N
Show answer and solution

Correct answer: B. 2000 N

**Convert:** 36 km/h = 10 m/s. Deceleration a = (0 - 10)/5 = -2 m/s². Braking force F = ma = 1000 × 2 = 2000 N.

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