alleryTwo springs k1 and k2 in series: equivalent spring constant:
A(k1 + k2)/2
BCannot be determined
Ck1 k2 / (k1 + k2)
Dk1 + k2
Answer & Solution
Correct answer: C. k1 k2 / (k1 + k2)
**Springs in series:** each carries same force, extensions add.
1/k_eq = 1/k1 + 1/k2, so k_eq = k1 k2 / (k1 + k2).
System more compliant (less stiff).
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