A simple pendulum of length 1 m has period T (g = 9.8). New length needed to double T:
A0.5 m
B1 m
C4 m
D2 m
Answer & Solution
Correct answer: C. 4 m
T ∝ √L. To double T, L must increase 4×.
So new L = 4 × 1 = 4 m.
(Original T ≈ 2.01 s; new T ≈ 4.02 s.)
Keep practising Unit 1C: Kinematics: Relative & Circular Motion
Browse all Unit 1C: Kinematics: Relative & Circular Motion questions for AP Physics 1, or explore more Physics topics.
Related questions
A solid sphere of mass M, radius R rolls without slipping down an incline of angle theta. For a hoop, disc, and solid sphere of same mass and radius rolling down an incline. Order A figure skater pulls in her arms during a spin. Her moment of inertia decreases. By conseTwo point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis throuA solid cylinder and a hollow cylinder of same mass and radius roll down an incline. WhichFor a body rolling without slipping with velocity v of center of mass:Kinetic energy of a rotating body with moment of inertia I and angular velocity omega:For a thin rod of mass M and length L, I about axis through center perpendicular to rod: