Two equal masses (3 kg each) connected by a light string over a frictionless pulley. One on smooth horizontal table, other hangs over edge. Acceleration?
Ag/2 = 5 m/s²
Bg/4 = 2.5 m/s²
Cg = 10 m/s²
DZero
Answer & Solution
Correct answer: A. g/2 = 5 m/s²
Hanging mass: T = m(g - a). Mass on table: T = ma. Equating: m(g - a) = ma → g - a = a → a = g/2 = 5 m/s². (Atwood-like setup with no friction.)
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