Practice free →
HomeJEE MainPhysicsNewton's Laws of Motion › A pendulum of mass m swings to amplitude angle θ…

A pendulum of mass m swings to amplitude angle θ. At the lowest point of swing, the TENSION in the string equals:

Amg
Bmg(2 − cos θ)
Cmg(3 − 2cos θ)
D2mg sin θ
Answer & Solution
Correct answer: C. mg(3 − 2cos θ)
At the lowest point: T − mg = mv²/L (centripetal). v² at bottom = 2gL(1 − cos θ) (energy conservation from amplitude). So T = mg + 2mg(1 − cos θ) = mg(3 − 2cos θ). For θ = 60°: T = mg(3 − 1) = 2mg.
Solve this in the app — JEE Main practice & 24k+ MCQs →
Related questions