A particle executing SHM has time period T. Time taken to go from extreme position (x = A) to x = A/2:
AT/4
BT/6
CT/8
DT/12
Answer & Solution
Correct answer: B. T/6
With x = A cos(ωt) starting at extreme: x = A/2 when cos(ωt) = 1/2, so ωt = π/3, hence t = T/(2π) × π/3 = T/6.
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