For SHM x = 5 sin(2πt), find amplitude and time period:
AA = 5, T = 2π s
BA = 5, T = 1 s
CA = 2π, T = 5 s
DA = 1, T = 5 s
Answer & Solution
Correct answer: B. A = 5, T = 1 s
Compare with x = A sin(ωt + φ): A = 5 (units), ω = 2π. T = 2π/ω = 1 s.
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