Time period of a simple pendulum of length L (small oscillations):
AT = 2π√(L/g)
BT = 2π√(g/L)
CT = √(L/g)
DT = 2π/L
Answer & Solution
Correct answer: A. T = 2π√(L/g)
T = 2π√(L/g) for small oscillations. Independent of mass. Doubling length increases T by factor √2.
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