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Indian Navy 10+2 B.Tech Cadet Chemistry — practice by topic

Browse 270 questions across 72 Chemistry topics. Choose what you want to revise, then open a question to check its answer and worked solution.

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Chemistry topics

Alcohols Phenols Ethers (72)Organic Chemistry (71)Alkenes (69)Polymers (69)Chemical Equilibrium (66)Atoms and Molecules (61)States of Matter (61)Classification of Elements (60)Classification of Elements and Periodicity (60)p-Block Elements (Groups 15-18) (60)S Block Elements (60)p-Block Elements (57)The p-Block Elements (57)Surface Chemistry (55)Solid State (51)Aldehydes Ketones (41)JEE Main 2023 Mixed (38)Atomic combinations (37)Atoms and Elements (37)Chemistry (37)Class9 Atom Structure (37)Structure of Atom (37)Organic Chemistry: Some Basic Principles and Techniques (36)Atomic Structure (35)Atomic Structure and Valency (35)Alcohols, Phenols and Ethers (34)Hydrocarbons (34)Coordination Compounds (33)Electrochemical Series (33)Haloalkanes and Haloarenes (33)Aldehydes, Ketones and Carboxylic Acids (32)Equilibrium (32)Equilibrium Constant (32)Periodic Classification of Elements (32)Classification of Elements and Periodicity in Properties (31)Periodic Classification (31)Periodic Table (31)Periodic Trends (31)The Periodic Table (31)Atoms (30)Chemical Bonding and Molecular Structure (30)Ideal and Non-Ideal Solutions (30)Ideal Solutions (30)Non-Ideal Solutions (30)Reactions in Aqueous Solution (30)Redox Reactions (30)d- and f-Block Elements (29)Electrochemistry (28)The d- and f-Block Elements (28)Chemical Bonding (27)Amines (26)Chemical Kinetics (26)Hydrogen (26)Redox & Electrochemistry (26)Surface Tension (26)Some Basic Concepts of Chemistry (25)Equipotential Surfaces (24)Surface Areas and Volumes (24)The Atom (24)Solutions (18)

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The potential developed between a metal rod and its solution due to oxidation is called:Read the answer and worked solution →When propene reacts with HBr in the presence of organic peroxides, the major product is:Read the answer and worked solution →Reduction of an aldehyde with $\mathrm{NaBH_4}$ or $\mathrm{LiAlH_4}$ produces:Read the answer and worked solution →The van't Hoff factor $i$ for a $0.01$ M aqueous solution of NaCl, assuming complete dissociation, is approximately:Read the answer and worked solution →

Worked practice questions

The potential developed between a metal rod and its solution due to oxidation is called:

  1. Reduction potential
  2. Oxidation potential
  3. Solubility potential
  4. Neutralization potential
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Correct answer: B. Oxidation potential

The notes define the potential developed between the rod and the solution in this case as oxidation potential, represented by $E(Zn/Zn^{2+})$.

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When propene reacts with HBr in the presence of organic peroxides, the major product is:

  1. propan-$1$-ol
  2. propane
  3. $2$-bromopropane
  4. $1$-bromopropane
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Correct answer: D. $1$-bromopropane

Peroxides switch the mechanism from ionic to free-radical (peroxide / Kharasch effect). The radical adds anti-Markovnikov so Br lands on the *less* substituted carbon — giving 1-bromopropane. The trap is option B (Markovnikov product) — that's the answer without peroxides. The peroxide effect is specific to HBr HCl and HI do not show it.

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Reduction of an aldehyde with $\mathrm{NaBH_4}$ or $\mathrm{LiAlH_4}$ produces:

  1. A carboxylic acid
  2. A secondary alcohol
  3. A primary alcohol
  4. An alkane
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Correct answer: C. A primary alcohol

Aldehydes ($\mathrm{R-CHO}$) are reduced to **primary** alcohols ($\mathrm{R-CH_2OH}$) because the carbonyl carbon ends up with just one $\mathrm{R}$ group on it. Ketones ($\mathrm{R_2C=O}$) reduce to *secondary* alcohols (option B) for the symmetric reason. Neither $\mathrm{NaBH_4}$ nor $\mathrm{LiAlH_4}$ goes all the way to alkane — that requires harsher conditions (Clemmensen, Wolff–Kishner).

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