Start learning →

Indian Navy 10+2 B.Tech Cadet Periodic Trends — practice questions

Explore 31 free Periodic Trends questions in Indian Navy 10+2 B.Tech Cadet Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

Practise Periodic Trends with Quill →

Periodic Trends questions and exercises with answers

Showing questions 1–30 of 31.

Across a period from left to right, the atomic radius generally:Read the answer and worked solution →Which element has the highest first ionization energy in period 2?Read the answer and worked solution →What is the valency of an element with electronic configuration 2, 8, 3?Read the answer and worked solution →Which of the following elements does not lose an electron easily?Read the answer and worked solution →Arrange the following elements in the order of their decreasing metallic character Na, Si, Cl, Mg, AlRead the answer and worked solution →Arrange the following elements in the order of their increasing non-metallic character Li, O, C, Be, FRead the answer and worked solution →On moving from left to right in a period in the periodic table, the size of the atom.Read the answer and worked solution →Match each scientist to their contributionRead the answer and worked solution →Ionic or covalent?Read the answer and worked solution →Complete the driver of bond formationRead the answer and worked solution →Single, double and triple bondsRead the answer and worked solution →True or false: Lewis structuresRead the answer and worked solution →Complete the definition of resonanceRead the answer and worked solution →Tap every bond parameter the chapter namesRead the answer and worked solution →True or false: ionic solidsRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Bonded pair or lone pair?Read the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Order the reasoning: why resonance is neededRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →True or false: what bond parameters affectRead the answer and worked solution →Bond parameters in useRead the answer and worked solution →Which parameter answers this?Read the answer and worked solution →True or false: resonanceRead the answer and worked solution →Order the steps: draw a Lewis structureRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Assertion and reason: structureRead the answer and worked solution →

Worked practice questions

Across a period from left to right, the atomic radius generally:

  1. Decreases
  2. Remains constant
  3. Increases
  4. First increases then decreases
Show answer and solution

Correct answer: A. Decreases

Atomic radius **decreases** from left to right across a period. Why: nuclear charge ($Z$) increases by 1 as you move right, pulling electrons closer. The added electron enters the same shell so screening barely increases — the net effect is stronger attraction and smaller radius. Across period 2: Li (152 pm) → Be → B → C → N → O → F (72 pm). Roughly halves. Down a group, atomic radius *increases* (electrons go into higher principal shells, further from nucleus).

Open this question →

Which element has the highest first ionization energy in period 2?

  1. Carbon (C)
  2. Oxygen (O)
  3. Neon (Ne)
  4. Lithium (Li)
Show answer and solution

Correct answer: C. Neon (Ne)

First ionization energy generally increases across a period because nuclear charge grows and atomic radius shrinks, making it harder to remove an outer electron. In period 2: Li (520) < Be (899) ≈ B (801) < C (1086) < N (1402) > O (1314) < F (1681) < **Ne (2081)** kJ/mol. Neon has the highest because it has a stable octet ($1s^2 2s^2 2p^6$, full $2p$). Removing an electron requires breaking that closed shell. Note two anomalies: B < Be (removing a $2p$ electron easier than $2s$) and O < N (paired $2p$ electron in O has extra repulsion).

Open this question →

What is the valency of an element with electronic configuration 2, 8, 3?

  1. Three
  2. Two
  3. Five
  4. Eight
Show answer and solution

Correct answer: A. Three

1. The element has 3 electrons in the outermost shell. 2. Valency for groups 1-2 and 13 is the number of valence electrons. 3. With 3 valence electrons, the element gives a valency of 3. 4. So the valency is three. 5. The element is aluminium with atomic number 13. _Source: syllabus Science Ch 5 'Periodic Classification of Elements'_

Open this question →

How to practise

  1. Choose a Periodic Trends question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

More Chemistry topics

Alcohols Phenols EthersOrganic ChemistryAlkenesPolymersChemical EquilibriumAtoms and MoleculesStates of MatterClassification of Elements