When propene reacts with HBr in the presence of organic peroxides, the major product is:
- propan-$1$-ol
- propane
- $2$-bromopropane
- $1$-bromopropane
Show answer and solution
Correct answer: D. $1$-bromopropane
Peroxides switch the mechanism from ionic to free-radical (peroxide / Kharasch effect). The radical adds anti-Markovnikov
so Br lands on the *less* substituted carbon — giving 1-bromopropane.
The trap is option B (Markovnikov product) — that's the answer without peroxides. The peroxide effect is specific to HBr
HCl and HI do not show it.