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Indian Navy 10+2 B.Tech Cadet Organic Chemistry — practice questions

Explore 71 free Organic Chemistry questions in Indian Navy 10+2 B.Tech Cadet Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Organic Chemistry questions and exercises with answers

Showing questions 1–30 of 71.

The minimum energy required to remove an electron from the ground state of a hydrogen atom is:Read the answer and worked solution →According to VSEPR theory, the shape of a molecule is determined byRead the answer and worked solution →The hybridisation of carbon in methane (CH₄) isRead the answer and worked solution →As per your syllabus, (ii), the Wurtz reaction uses which reagent + solvent for coupling alkyl halides?Read the answer and worked solution →As per your syllabus, the rate of HALOGENATION of alkanes (F₂, Cl₂, Br₂, I₂) decreases in which order?Read the answer and worked solution →As per your syllabus, the rate-determining intermediate in HBr + propene addition is which species?Read the answer and worked solution →As per your syllabus, addition of water to ethyne in dilute H₂SO₄ with HgSO₄ catalyst gives which final product?Read the answer and worked solution →As per your syllabus, halogenation, the role of anhydrous AlCl₃ (or FeCl₃) in benzene chlorination is which?Read the answer and worked solution →As per your syllabus, which of the following groups is a META-directing substituent on benzene?Read the answer and worked solution →As per your syllabus, halogens (-Cl, -Br) on benzene are which kind of directors despite their deactivating -I effect?Read the answer and worked solution →What is the valency of an element with electronic configuration 2, 8, 3?Read the answer and worked solution →Which of the following elements does not lose an electron easily?Read the answer and worked solution →Arrange the following elements in the order of their decreasing metallic character Na, Si, Cl, Mg, AlRead the answer and worked solution →Arrange the following elements in the order of their increasing non-metallic character Li, O, C, Be, FRead the answer and worked solution →On moving from left to right in a period in the periodic table, the size of the atom.Read the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →

Worked practice questions

The minimum energy required to remove an electron from the ground state of a hydrogen atom is:

  1. $3.4\,\text{eV}$
  2. $13.6\,\text{eV}$
  3. $27.2\,\text{eV}$
  4. $1.51\,\text{eV}$
Show answer and solution

Correct answer: B. $13.6\,\text{eV}$

Ionisation energy is the energy required to take the electron from $n = 1$ to $n = \infty$. $E_\infty - E_1 = 0 - (-13.6) = 13.6\,\text{eV}$. The value $27.2\,\text{eV}$ is the magnitude of the potential energy in the ground state, not the ionisation energy.

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According to VSEPR theory, the shape of a molecule is determined by

  1. the colour of the element
  2. temperature
  3. repulsion between electron pairs around the central atom
  4. the atomic mass
Show answer and solution

Correct answer: C. repulsion between electron pairs around the central atom

VSEPR: electron pairs (bonding + lone) arrange to minimise repulsion, fixing the molecular geometry.

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The hybridisation of carbon in methane (CH₄) is

  1. sp
  2. sp³
  3. sp³d
  4. sp²
Show answer and solution

Correct answer: B. sp³

Four sigma bonds, tetrahedral → sp³ hybridisation.

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More Chemistry topics

Alcohols Phenols EthersAlkenesPolymersChemical EquilibriumAtoms and MoleculesStates of MatterClassification of ElementsClassification of Elements and Periodicity