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Indian Navy 10+2 B.Tech Cadet Coordination Compounds — practice questions

Explore 33 free Coordination Compounds questions in Indian Navy 10+2 B.Tech Cadet Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Coordination Compounds questions and exercises with answers

Showing questions 1–30 of 33.

Among $\mathrm{Sc^{3+}}$, $\mathrm{Ti^{4+}}$, $\mathrm{V^{2+}}$ and $\mathrm{Zn^{2+}}$, which is **coloured** in aqueous solution?Read the answer and worked solution →Which complex is paramagnetic?Read the answer and worked solution →In strong-field octahedral, electron filling order in d-orbitals follows:Read the answer and worked solution →Crystal field splitting for d-orbitals in octahedral field. The five d orbitals split into:Read the answer and worked solution →Magnetic moment for [Mn(H₂O)₆]²⁺ (high spin, d⁵):Read the answer and worked solution →Optical isomers of [Co(en)₃]³⁺ (en = ethylenediamine):Read the answer and worked solution →The unusual stability of EDTA-metal complexes is mainly due to the:Read the answer and worked solution →Sort each ligand by how many donor atoms it usesRead the answer and worked solution →Match each term to its definitionRead the answer and worked solution →True or false: coordination numberRead the answer and worked solution →Counting the coordination numberRead the answer and worked solution →Match each complex to its shapeRead the answer and worked solution →Sort each complex by its geometryRead the answer and worked solution →Complete the coordination sphere ruleRead the answer and worked solution →True or false: ambidentate ligandsRead the answer and worked solution →Chelate or ambidentate?Read the answer and worked solution →Complete the definition of oxidation numberRead the answer and worked solution →Match each theory to what it explainsRead the answer and worked solution →Tap every failing of Valence Bond TheoryRead the answer and worked solution →True or false: the theories and their limitsRead the answer and worked solution →Complete Werner's postulateRead the answer and worked solution →Synergic bonding in metal carbonylsRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Order the steps: read a formula like K₄[Fe(CN)₆]Read the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Tap every statement true of a chelate complexRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →

Worked practice questions

Among $\mathrm{Sc^{3+}}$, $\mathrm{Ti^{4+}}$, $\mathrm{V^{2+}}$ and $\mathrm{Zn^{2+}}$, which is **coloured** in aqueous solution?

  1. $\mathrm{Sc^{3+}}$
  2. $\mathrm{Ti^{4+}}$
  3. $\mathrm{V^{2+}}$
  4. $\mathrm{Zn^{2+}}$
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Correct answer: C. $\mathrm{V^{2+}}$

Colour in transition-metal aquo ions comes from $d$-$d$ transitions, which require partially-filled $d$-orbitals. $\mathrm{Sc^{3+}}$ ($d^0$), $\mathrm{Ti^{4+}}$ ($d^0$) and $\mathrm{Zn^{2+}}$ ($d^{10}$) all have either empty or completely filled d-shells, so they are colourless. $\mathrm{V^{2+}}$ is $d^3$, giving a violet colour in solution.

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Which complex is paramagnetic?

  1. Has UNPAIRED electrons in d-orbitals
  2. Only octahedral
  3. Strong-field complexes always
  4. Diamagnetic ones with all paired electrons
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Correct answer: A. Has UNPAIRED electrons in d-orbitals

Paramagnetic = has unpaired electrons (attracted to magnetic field). For d-block complexes, depends on electron configuration in t2g/eg orbitals. High-spin complexes have more unpaired e⁻ than low-spin.

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In strong-field octahedral, electron filling order in d-orbitals follows:

  1. Random with pairing
  2. Hund's rule fills t2g and eg simultaneously
  3. Random
  4. Fills t2g completely first (low spin), then eg
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Correct answer: D. Fills t2g completely first (low spin), then eg

**Strong-field:** large Δ_oct, so pairing in lower t2g is more favorable than promoting to higher eg. **Result:** low-spin configurations (e.g., d⁶ as t2g⁶ eg⁰, all paired = diamagnetic). **Weak-field:** small Δ, Hund's rule favors high-spin.

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