For first-order, integrated rate law:
- ln([A]₀/[A]) = kt
- [A]₀ - [A] = kt
- 1/[A] - 1/[A]₀ = kt
- [A] = constant
Show answer and solution
Correct answer: A. ln([A]₀/[A]) = kt
d[A]/dt = -k[A] integrates to ln([A]₀/[A]) = kt, or [A] = [A]₀ e^(-kt). Exponential decay.
Plot ln[A] vs t is straight line with slope -k.