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Indian Navy 10+2 B.Tech Cadet Amines — practice questions

Explore 26 free Amines questions in Indian Navy 10+2 B.Tech Cadet Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Amines questions and exercises with answers

Showing questions 1–26 of 26.

Across a period from left to right, the atomic radius generally:Read the answer and worked solution →Which element has the highest first ionization energy in period 2?Read the answer and worked solution →Match each scientist to their contributionRead the answer and worked solution →Ionic or covalent?Read the answer and worked solution →Complete the driver of bond formationRead the answer and worked solution →Single, double and triple bondsRead the answer and worked solution →True or false: Lewis structuresRead the answer and worked solution →Complete the definition of resonanceRead the answer and worked solution →Tap every bond parameter the chapter namesRead the answer and worked solution →True or false: ionic solidsRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Bonded pair or lone pair?Read the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Order the reasoning: why resonance is neededRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →True or false: what bond parameters affectRead the answer and worked solution →Bond parameters in useRead the answer and worked solution →Which parameter answers this?Read the answer and worked solution →True or false: resonanceRead the answer and worked solution →Order the steps: draw a Lewis structureRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Assertion and reason: structureRead the answer and worked solution →Flip and pair: parameter with what it measuresRead the answer and worked solution →

Worked practice questions

Across a period from left to right, the atomic radius generally:

  1. Decreases
  2. Remains constant
  3. Increases
  4. First increases then decreases
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Correct answer: A. Decreases

Atomic radius **decreases** from left to right across a period. Why: nuclear charge ($Z$) increases by 1 as you move right, pulling electrons closer. The added electron enters the same shell so screening barely increases — the net effect is stronger attraction and smaller radius. Across period 2: Li (152 pm) → Be → B → C → N → O → F (72 pm). Roughly halves. Down a group, atomic radius *increases* (electrons go into higher principal shells, further from nucleus).

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Which element has the highest first ionization energy in period 2?

  1. Carbon (C)
  2. Oxygen (O)
  3. Neon (Ne)
  4. Lithium (Li)
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Correct answer: C. Neon (Ne)

First ionization energy generally increases across a period because nuclear charge grows and atomic radius shrinks, making it harder to remove an outer electron. In period 2: Li (520) < Be (899) ≈ B (801) < C (1086) < N (1402) > O (1314) < F (1681) < **Ne (2081)** kJ/mol. Neon has the highest because it has a stable octet ($1s^2 2s^2 2p^6$, full $2p$). Removing an electron requires breaking that closed shell. Note two anomalies: B < Be (removing a $2p$ electron easier than $2s$) and O < N (paired $2p$ electron in O has extra repulsion).

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Match each scientist to their contribution

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Matching pairs
  1. Left
    Kossel
    Right
    electrostatic attraction between ions, giving electrovalency
  2. Left
    Lewis
    Right
    covalent bonding by sharing electron pairs
  3. Left
    Lewis dot symbols
    Right
    show the valence electrons of an atom
  4. Left
    Lewis dot structures
    Right
    show the bonding in a molecule
The chapter opens with these two accounts of bonding. Source: syllabus Chemistry, Ch 4 Chemical Bonding and Molecular Structure.

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