Start learning →

Indian Navy 10+2 B.Tech Cadet Aldehydes, Ketones and Carboxylic Acids — practice questions

Explore 32 free Aldehydes, Ketones and Carboxylic Acids questions in Indian Navy 10+2 B.Tech Cadet Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

Practise Aldehydes, Ketones and Carboxylic Acids with Quill →

Aldehydes, Ketones and Carboxylic Acids questions and exercises with answers

Showing questions 1–30 of 32.

Reduction of an aldehyde with $\mathrm{NaBH_4}$ or $\mathrm{LiAlH_4}$ produces:Read the answer and worked solution →As per your syllabus, (ii), the Wurtz reaction uses which reagent + solvent for coupling alkyl halides?Read the answer and worked solution →As per your syllabus, the rate of HALOGENATION of alkanes (F₂, Cl₂, Br₂, I₂) decreases in which order?Read the answer and worked solution →As per your syllabus, the rate-determining intermediate in HBr + propene addition is which species?Read the answer and worked solution →As per your syllabus, addition of water to ethyne in dilute H₂SO₄ with HgSO₄ catalyst gives which final product?Read the answer and worked solution →As per your syllabus, halogenation, the role of anhydrous AlCl₃ (or FeCl₃) in benzene chlorination is which?Read the answer and worked solution →As per your syllabus, which of the following groups is a META-directing substituent on benzene?Read the answer and worked solution →As per your syllabus, halogens (-Cl, -Br) on benzene are which kind of directors despite their deactivating -I effect?Read the answer and worked solution →Match each scientist to their contributionRead the answer and worked solution →Ionic or covalent?Read the answer and worked solution →Complete the driver of bond formationRead the answer and worked solution →Single, double and triple bondsRead the answer and worked solution →True or false: Lewis structuresRead the answer and worked solution →Complete the definition of resonanceRead the answer and worked solution →Tap every bond parameter the chapter namesRead the answer and worked solution →True or false: ionic solidsRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Bonded pair or lone pair?Read the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Order the reasoning: why resonance is neededRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →True or false: what bond parameters affectRead the answer and worked solution →Bond parameters in useRead the answer and worked solution →Which parameter answers this?Read the answer and worked solution →True or false: resonanceRead the answer and worked solution →Order the steps: draw a Lewis structureRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →

Worked practice questions

Reduction of an aldehyde with $\mathrm{NaBH_4}$ or $\mathrm{LiAlH_4}$ produces:

  1. A carboxylic acid
  2. A secondary alcohol
  3. A primary alcohol
  4. An alkane
Show answer and solution

Correct answer: C. A primary alcohol

Aldehydes ($\mathrm{R-CHO}$) are reduced to **primary** alcohols ($\mathrm{R-CH_2OH}$) because the carbonyl carbon ends up with just one $\mathrm{R}$ group on it. Ketones ($\mathrm{R_2C=O}$) reduce to *secondary* alcohols (option B) for the symmetric reason. Neither $\mathrm{NaBH_4}$ nor $\mathrm{LiAlH_4}$ goes all the way to alkane — that requires harsher conditions (Clemmensen, Wolff–Kishner).

Open this question →

As per your syllabus, (ii), the Wurtz reaction uses which reagent + solvent for coupling alkyl halides?

  1. NaOH and CaO
  2. Zinc in dilute HCl
  3. Pt or Pd catalyst
  4. Sodium in dry ether
Show answer and solution

Correct answer: D. Sodium in dry ether

Your syllabus: Wurtz: 2 R-X + 2 Na → R-R + 2 NaX in dry ether. Used to make higher alkanes with even carbon count.

Open this question →

As per your syllabus, the rate of HALOGENATION of alkanes (F₂, Cl₂, Br₂, I₂) decreases in which order?

  1. F₂ > Cl₂ > Br₂ > I₂
  2. I₂ > Br₂ > Cl₂ > F₂
  3. Br₂ > Cl₂ > F₂ > I₂
  4. Cl₂ > F₂ > Br₂ > I₂
Show answer and solution

Correct answer: A. F₂ > Cl₂ > Br₂ > I₂

syllabus substitution: F₂ > Cl₂ > Br₂ > I₂ (fluorination is too violent, iodination reversible).

Open this question →

How to practise

  1. Choose a Aldehydes, Ketones and Carboxylic Acids question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

More Chemistry topics

Alcohols Phenols EthersOrganic ChemistryAlkenesPolymersChemical EquilibriumAtoms and MoleculesStates of MatterClassification of Elements