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Indian Navy 10+2 B.Tech Cadet Surface Chemistry — practice questions

Explore 55 free Surface Chemistry questions in Indian Navy 10+2 B.Tech Cadet Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Surface Chemistry questions and exercises with answers

Showing questions 1–30 of 55.

Across a period from left to right, the atomic radius generally:Read the answer and worked solution →Which element has the highest first ionization energy in period 2?Read the answer and worked solution →According to VSEPR theory, the shape of a molecule is determined byRead the answer and worked solution →The hybridisation of carbon in methane (CH₄) isRead the answer and worked solution →HENRY'S LAW states that at constant temperature:Read the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Which principle is being described?Read the answer and worked solution →Flip and pair: symbol with meaningRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Tap every statement true of the Schrodinger modelRead the answer and worked solution →Reading the models backRead the answer and worked solution →Assertion and reason: filling orbitalsRead the answer and worked solution →True or false: shells and subshellsRead the answer and worked solution →

Worked practice questions

Across a period from left to right, the atomic radius generally:

  1. Decreases
  2. Remains constant
  3. Increases
  4. First increases then decreases
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Correct answer: A. Decreases

Atomic radius **decreases** from left to right across a period. Why: nuclear charge ($Z$) increases by 1 as you move right, pulling electrons closer. The added electron enters the same shell so screening barely increases — the net effect is stronger attraction and smaller radius. Across period 2: Li (152 pm) → Be → B → C → N → O → F (72 pm). Roughly halves. Down a group, atomic radius *increases* (electrons go into higher principal shells, further from nucleus).

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Which element has the highest first ionization energy in period 2?

  1. Carbon (C)
  2. Oxygen (O)
  3. Neon (Ne)
  4. Lithium (Li)
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Correct answer: C. Neon (Ne)

First ionization energy generally increases across a period because nuclear charge grows and atomic radius shrinks, making it harder to remove an outer electron. In period 2: Li (520) < Be (899) ≈ B (801) < C (1086) < N (1402) > O (1314) < F (1681) < **Ne (2081)** kJ/mol. Neon has the highest because it has a stable octet ($1s^2 2s^2 2p^6$, full $2p$). Removing an electron requires breaking that closed shell. Note two anomalies: B < Be (removing a $2p$ electron easier than $2s$) and O < N (paired $2p$ electron in O has extra repulsion).

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According to VSEPR theory, the shape of a molecule is determined by

  1. the colour of the element
  2. temperature
  3. repulsion between electron pairs around the central atom
  4. the atomic mass
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Correct answer: C. repulsion between electron pairs around the central atom

VSEPR: electron pairs (bonding + lone) arrange to minimise repulsion, fixing the molecular geometry.

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More Chemistry topics

Alcohols Phenols EthersOrganic ChemistryAlkenesPolymersChemical EquilibriumAtoms and MoleculesStates of MatterClassification of Elements