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NEET UG Aldehydes, Ketones and Carboxylic Acids — practice questions — page 2

Explore 151 free Aldehydes, Ketones and Carboxylic Acids questions in NEET UG Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Aldehydes, Ketones and Carboxylic Acids questions and exercises with answers

Showing questions 31–60 of 151.

**Cannizzaro's reaction** is given by aldehydes that haveRead the answer and worked solution →**Rosenmund's reduction** converts an acyl chloride to an aldehyde usingRead the answer and worked solution →**Stephen's reduction** converts a nitrile $RCN$ into an aldehyde usingRead the answer and worked solution →In the **Etard reaction**, toluene is oxidised to benzaldehyde byRead the answer and worked solution →**Gatterman–Koch reaction** formylates benzene usingRead the answer and worked solution →**Clemmensen reduction** converts $>C=O$ to $>CH_2$ usingRead the answer and worked solution →**Wolff–Kishner reduction** uses which reagent to convert $>C=O$ to $>CH_2$?Read the answer and worked solution →The **Hell–Volhard–Zelinsky (HVZ) reaction** converts a carboxylic acid (with $\alpha$-H) to an $\alpha$-halo acid usingRead the answer and worked solution →**Hoffmann ammonolysis** of alkyl halide with excess $NH_3$ in sealed tube primarily givesRead the answer and worked solution →**Diazotisation** of a primary aromatic amine uses $NaNO_2 + HCl$ atRead the answer and worked solution →**Sandmeyer's reaction** converts $ArN_2^+X^-$ to $ArCl$ usingRead the answer and worked solution →Sandmeyer's reaction proceeds via which type of intermediate?Read the answer and worked solution →The **Gattermann reaction** (not Gatterman–Koch) converts $ArN_2^+X^-$ to $ArX$ usingRead the answer and worked solution →The **Balz–Schiemann reaction** converts $ArN_2^+$ to $ArF$ via which intermediate?Read the answer and worked solution →Which of the following named reactions does **NOT** require an $\alpha$-hydrogen on the substrate?Read the answer and worked solution →Identify the correct conversion: $CH_3CN \xrightarrow{?} CH_3CHO$ (one step).Read the answer and worked solution →As per your syllabus, nitration, the actual ELECTROPHILE that attacks benzene in HNO₃ + H₂SO₄ mixture is which species?Read the answer and worked solution →As per your syllabus, halogenation, the role of anhydrous AlCl₃ (or FeCl₃) in benzene chlorination is which?Read the answer and worked solution →As per your syllabus, Friedel-Crafts ALKYLATION of benzene uses which reagent system?Read the answer and worked solution →As per your syllabus, Friedel-Crafts ACYLATION of benzene uses an acyl halide + AlCl₃ to generate which electrophile?Read the answer and worked solution →As per your syllabus, which of the following groups is a META-directing substituent on benzene?Read the answer and worked solution →As per your syllabus, halogens (-Cl, -Br) on benzene are which kind of directors despite their deactivating -I effect?Read the answer and worked solution →The general formula for alkanes is:Read the answer and worked solution →Tollens' reagent gives a silver mirror with:Read the answer and worked solution →The IUPAC name of the simplest aldehyde, $\mathrm{HCHO}$, isRead the answer and worked solution →The carbonyl carbon in an aldehyde or ketone isRead the answer and worked solution →Which carboxylic acid has the highest $K_a$ (i.e. is the most acidic)?Read the answer and worked solution →The reaction of formaldehyde with concentrated NaOH is calledRead the answer and worked solution →Match each named organic reaction to its description.Read the answer and worked solution →Match each named organic reaction to its description.Read the answer and worked solution →

Worked practice questions

**Cannizzaro's reaction** is given by aldehydes that have

  1. no $\alpha$-hydrogen
  2. two $\alpha$-hydrogens
  3. only aromatic aldehydes
  4. one $\alpha$-hydrogen
Show answer and solution

Correct answer: A. no $\alpha$-hydrogen

Cannizzaro is the disproportionation pathway taken by aldehydes WITHOUT $\alpha$-H (e.g. HCHO, $C_6H_5CHO$, $(CH_3)_3CCHO$), since they cannot enolise. With $\alpha$-H, aldol dominates.

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**Rosenmund's reduction** converts an acyl chloride to an aldehyde using

  1. $H_2/Pd-BaSO_4$ (poisoned)
  2. $LiAlH_4$
  3. $Zn/HCl$
  4. $NaBH_4$
Show answer and solution

Correct answer: A. $H_2/Pd-BaSO_4$ (poisoned)

$RCOCl + H_2 \xrightarrow{Pd/BaSO_4} RCHO + HCl$. Catalyst is deliberately poisoned (with quinoline/sulphur) to stop over-reduction to the alcohol.

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**Stephen's reduction** converts a nitrile $RCN$ into an aldehyde using

  1. $LiAlH_4$
  2. $Zn-Hg/HCl$
  3. $SnCl_2$ in $HCl$, then $H_2O$
  4. $Na/EtOH$
Show answer and solution

Correct answer: C. $SnCl_2$ in $HCl$, then $H_2O$

$RCN + SnCl_2/HCl \to RCH=NH\cdot HCl$ (imine HCl salt), which on hydrolysis gives $RCHO$. Useful when an aldehyde is needed from a 1°-amine precursor.

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More Chemistry topics

Amines and BiomoleculesChemical KineticsEquilibriumRedox ReactionsHydrocarbonsChemical Bonding and Molecular StructureSolutionsStructure of Atom