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**Gatterman–Koch reaction** formylates benzene using
A$RCOCl$ with $AlCl_3$
B$CHCl_3$ with aq. $NaOH$
C$CO + HCl$ with $AlCl_3$/$CuCl$
D$HCHO$ with conc. $H_2SO_4$
Answer & Solution
Correct answer: C. $CO + HCl$ with $AlCl_3$/$CuCl$
$C_6H_6 + CO + HCl \xrightarrow{AlCl_3, CuCl} C_6H_5CHO$. Equivalent to a Friedel–Crafts acylation with the in-situ generated formyl cation $HC≡O^+$.
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