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The **Gattermann reaction** (not Gatterman–Koch) converts $ArN_2^+X^-$ to $ArX$ using
A$Cu$ powder / $HX$
B$LiAlH_4$
C$Cu_2X_2$ / $HX$
D$NaOH$
Answer & Solution
Correct answer: A. $Cu$ powder / $HX$
Gattermann uses freshly precipitated **Cu powder** with the corresponding HX. Sandmeyer uses $Cu_2X_2$. Gattermann gives lower yields but uses simpler reagents.
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