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**Sandmeyer's reaction** converts $ArN_2^+X^-$ to $ArCl$ using
A$NaOH$
B$Br_2/FeBr_3$
C$Zn/HCl$
D$Cu_2Cl_2/HCl$
Answer & Solution
Correct answer: D. $Cu_2Cl_2/HCl$
Sandmeyer: cuprous halide is the key reagent — $Cu_2Cl_2/HCl \to ArCl$, $Cu_2Br_2/HBr \to ArBr$, $CuCN/KCN \to ArCN$. Mechanism is radical (single-electron transfer from Cu(I)).
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