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**Clemmensen reduction** converts $>C=O$ to $>CH_2$ using
A$LiAlH_4$
B$NH_2NH_2/KOH/\Delta$
C$H_2/Ni$
D$Zn(Hg)/conc.\,HCl$
Answer & Solution
Correct answer: D. $Zn(Hg)/conc.\,HCl$
Acidic conditions ($Zn$ amalgam + conc. HCl). Reduces ketones/aldehydes all the way to methylene. Use Wolff–Kishner instead if the substrate is base-stable but acid-sensitive.
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