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**Wolff–Kishner reduction** uses which reagent to convert $>C=O$ to $>CH_2$?
A$NH_2NH_2$ then $KOH/\Delta$
B$O_3/Zn$
C$NaBH_4$
D$Zn(Hg)/HCl$
Answer & Solution
Correct answer: A. $NH_2NH_2$ then $KOH/\Delta$
$>C=O \xrightarrow{NH_2NH_2} >C=N-NH_2 \xrightarrow{KOH, \Delta} >CH_2 + N_2\uparrow$. Basic conditions — ideal when the substrate cannot tolerate the acidic Clemmensen conditions.
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