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AP Intermediate 2nd Year Electric Charges and Fields — practice questions — page 2

Explore 103 free Electric Charges and Fields questions in AP Intermediate 2nd Year Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Electric Charges and Fields questions and exercises with answers

Showing questions 31–60 of 103.

The potential at a distance 0.30 m from a point charge of +20 nC is (k = 9 × 10⁹ N m² C⁻²)Read the answer and worked solution →A parallel-plate capacitor in vacuum has plate area A and separation d. Its capacitance isRead the answer and worked solution →Three capacitors of 2 µF each are connected in series. The equivalent capacitance isRead the answer and worked solution →The work done in bringing a charge q from infinity to a point where the potential is V isRead the answer and worked solution →Two capacitors of 4 µF and 6 µF are connected in parallel and charged by a 10 V battery. The total charge stored isRead the answer and worked solution →When the separation between the plates of an air parallel-plate capacitor is doubled (keeping plate area constant), the capacitanceRead the answer and worked solution →An electric dipole of moment p is placed in a uniform field E. The work done to rotate it from the orientation θ = 0 (aligned with the field) to θ = 180° isRead the answer and worked solution →A 5 µF capacitor is charged to 200 V. The energy stored in it isRead the answer and worked solution →An isolated conducting sphere of radius R carries a charge Q. The electric potential at its centre is (V(∞) = 0)Read the answer and worked solution →Four equal point charges q sit at the corners of a square of side d. The work needed to assemble this configuration from infinity isRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Coulomb's Law — Gap FillRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Quantity to UnitRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Conductor or InsulatorRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Gauss's Law — MemoryRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Tap Like-Charge PairsRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Field at a PointRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Dipole or Monopole FieldRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Dipole Moment — Gap FillRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Force on Dipole in FieldRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Electric Field — TypingRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Quantity to FormulaRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Tap Field-Line PropertiesRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Field Inside or OutsideRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Capacitance — Gap FillRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Field of a Charged ShellRead the answer and worked solution →NEET · Physics · Capacitors — Series or ParallelRead the answer and worked solution →Drop each fact inside or outsideRead the answer and worked solution →Match each electrostatic termRead the answer and worked solution →True or false: electrostaticsRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Electric Field — TypingRead the answer and worked solution →

Worked practice questions

The potential at a distance 0.30 m from a point charge of +20 nC is (k = 9 × 10⁹ N m² C⁻²)

  1. 1200 V
  2. 900 V
  3. 600 V
  4. 300 V
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Correct answer: C. 600 V

1. V = kq / r. 2. V = (9 × 10⁹)(20 × 10⁻⁹) / 0.30. 3. V = 180 / 0.30 = 600 V. _Source: syllabus Physics Part I, Ch 2 §2.3, mirrors Example 2.1 style_

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A parallel-plate capacitor in vacuum has plate area A and separation d. Its capacitance is

  1. ε₀ A d
  2. A / (ε₀ d)
  3. ε₀ A / d
  4. ε₀ d / A
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Correct answer: C. ε₀ A / d

1. For a parallel-plate capacitor, σ = Q / A and E = σ / ε₀. 2. V between plates = E × d = Q d / (ε₀ A). 3. C = Q / V = ε₀ A / d. _Source: syllabus Physics Part I, Ch 2 §2.12_

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Three capacitors of 2 µF each are connected in series. The equivalent capacitance is

  1. 2 µF
  2. 2/3 µF
  3. 6 µF
  4. 1/6 µF
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Correct answer: B. 2/3 µF

1. In series, 1/Cₑ = 1/C + 1/C + 1/C = 3/C. 2. Cₑ = C/3 = 2/3 µF. 3. Option (A) is the parallel result, so the trap is for students who mix the rules. _Source: syllabus Physics Part I, Ch 2 §2.14.1_

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