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A parallel-plate capacitor in vacuum has plate area A and separation d. Its capacitance is
A{'text': 'ε₀ A d', 'label': 'A'}
B{'text': 'A / (ε₀ d)', 'label': 'B'}
C{'text': 'ε₀ A / d', 'label': 'C'}
D{'text': 'ε₀ d / A', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'ε₀ A / d', 'label': 'C'}
1. For a parallel-plate capacitor, σ = Q / A and E = σ / ε₀.
2. V between plates = E × d = Q d / (ε₀ A).
3. C = Q / V = ε₀ A / d.
_Source: NCERT Class 12 Physics Part I, Ch 2 §2.12_
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