A 5 µF capacitor is charged to 200 V. The energy stored in it is
A0.1 J
B0.05 J
C1.0 J
D0.5 J
Answer & Solution
Correct answer: A. 0.1 J
1. U = ½ C V².
2. U = 0.5 × 5 × 10⁻⁶ × (200)² = 0.5 × 5 × 10⁻⁶ × 4 × 10⁴.
3. U = 10⁻¹ = 0.1 J.
_Source: syllabus Physics Part I, Ch 2 §2.15_
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