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AP Intermediate 2nd Year Current Electricity — practice questions

Explore 88 free Current Electricity questions in AP Intermediate 2nd Year Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Current Electricity questions and exercises with answers

Showing questions 1–30 of 88.

Estimate the drift speed of electrons in a copper wire carrying 1.5 A with cross-section 1.0×10⁻⁷ m² and n = 8.5×10²⁸ m⁻³ (e = 1.6×10⁻¹⁹ C):Read the answer and worked solution →Two cells, each of emf 1.5 V and internal resistance 0.5 Ω, are connected in series across a 2 Ω resistor. The current through the resistor is:Read the answer and worked solution →Two identical cells, each of emf 1.5 V and internal resistance 0.5 Ω, are connected in parallel across a 1 Ω resistor. The current through the resistor is:Read the answer and worked solution →The maximum current that can be drawn from a cell of emf 1.5 V and internal resistance 0.3 Ω is:Read the answer and worked solution →A Wheatstone bridge is balanced with arms P = 10 Ω, Q = 20 Ω and R = 15 Ω. The unknown resistance S is:Read the answer and worked solution →A 3 Ω resistor is connected in series with a parallel combination of a 6 Ω and a 3 Ω resistor. The equivalent resistance of the network is:Read the answer and worked solution →NEET · Physics · Kirchhoff's LawsRead the answer and worked solution →A galvanometer of resistance G can be converted into a voltmeter of range V by connecting in series a high resistance R given by:Read the answer and worked solution →Two 100-W bulbs are connected in series across 220 V. The total power consumed is:Read the answer and worked solution →True or false: what emf actually isRead the answer and worked solution →Complete the statement of Ohm's lawRead the answer and worked solution →Tap every way Ohm's law can failRead the answer and worked solution →Match each device or material to its behaviourRead the answer and worked solution →Sort each material by its resistivityRead the answer and worked solution →Complete the resistance relationRead the answer and worked solution →True or false: resistance and resistivityRead the answer and worked solution →Match each of Kirchhoff's rules to what it conservesRead the answer and worked solution →Kirchhoff's rulesRead the answer and worked solution →Order the steps: find an unknown resistance with a Wheatstone bridgeRead the answer and worked solution →True or false: internal resistanceRead the answer and worked solution →Which quantity is which?Read the answer and worked solution →Assertion and reasonRead the answer and worked solution →Charge carriersRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Tap every statement true of drift velocityRead the answer and worked solution →Complete the temperature coefficient definitionRead the answer and worked solution →Flip and pair: symbol with quantityRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →

Worked practice questions

Estimate the drift speed of electrons in a copper wire carrying 1.5 A with cross-section 1.0×10⁻⁷ m² and n = 8.5×10²⁸ m⁻³ (e = 1.6×10⁻¹⁹ C):

  1. ≈1.1×10⁻³ m s⁻¹
  2. ≈1.1 m s⁻¹
  3. ≈1.1×10⁻⁶ m s⁻¹
  4. ≈3×10⁸ m s⁻¹
Show answer and solution

Correct answer: A. ≈1.1×10⁻³ m s⁻¹

v_d = I/(neA) = 1.5 / (8.5×10²⁸ × 1.6×10⁻¹⁹ × 1.0×10⁻⁷) ≈ 1.1×10⁻³ m s⁻¹ — only a few mm per second, showing drift is very slow.

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Two cells, each of emf 1.5 V and internal resistance 0.5 Ω, are connected in series across a 2 Ω resistor. The current through the resistor is:

  1. 1.0 A
  2. 1.5 A
  3. 3.0 A
  4. 0.75 A
Show answer and solution

Correct answer: A. 1.0 A

Series cells: ε_eq = 1.5 + 1.5 = 3 V and r_eq = 0.5 + 0.5 = 1 Ω, so I = ε_eq/(R + r_eq) = 3/(2+1) = 1.0 A.

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Two identical cells, each of emf 1.5 V and internal resistance 0.5 Ω, are connected in parallel across a 1 Ω resistor. The current through the resistor is:

  1. 0.6 A
  2. 1.2 A
  3. 3.0 A
  4. 1.5 A
Show answer and solution

Correct answer: B. 1.2 A

Identical cells in parallel: ε_eq = 1.5 V, r_eq = 0.5/2 = 0.25 Ω We have I = 1.5/(1 + 0.25). So I = 1.2 A.

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