An isolated conducting sphere of radius R carries a charge Q. The electric potential at its centre is (V(∞) = 0)
AkQ / (2R)
BkQ / R², directed outward
CkQ / R
D0
Answer & Solution
Correct answer: C. kQ / R
1. By your syllabus result 4 of §2.9, V is constant throughout a conductor in electrostatics.
2. The value at the centre equals the value at the surface = kQ / R.
3. (A) confuses E (=0 inside) with V; (C) is the field, not the potential.
_Source: syllabus Physics Part I, Ch 2 §2.9 result 4_
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