The potential at a distance 0.30 m from a point charge of +20 nC is (k…

Question

The potential at a distance 0.30 m from a point charge of +20 nC is (k = 9 × 10⁹ N m² C⁻²)

Accepted Answer

C. {'text': '600 V', 'label': 'C'}

1. V = kq / r.
2. V = (9 × 10⁹)(20 × 10⁻⁹) / 0.30.
3. V = 180 / 0.30 = 600 V.
_Source: NCERT Class 12 Physics Part I, Ch 2 §2.3, mirrors Example 2.1 style_

Answer

{'text': '1200 V', 'label': 'A'}

Answer

{'text': '900 V', 'label': 'B'}

Answer

{'text': '300 V', 'label': 'D'}