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Three capacitors of 2 µF each are connected in series. The equivalent capacitance is
A{'text': '2 µF', 'label': 'A'}
B{'text': '2/3 µF', 'label': 'B'}
C{'text': '6 µF', 'label': 'C'}
D{'text': '1/6 µF', 'label': 'D'}
Answer & Solution
Correct answer: B. {'text': '2/3 µF', 'label': 'B'}
1. In series, 1/Cₑ = 1/C + 1/C + 1/C = 3/C.
2. Cₑ = C/3 = 2/3 µF.
3. Option (A) is the parallel result, so the trap is for students who mix the rules.
_Source: NCERT Class 12 Physics Part I, Ch 2 §2.14.1_
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