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Four equal point charges q sit at the corners of a square of side d. The work needed to assemble this configuration from infinity is
A{'text': '(kq²/d)(2 + 1/√2)', 'label': 'A'}
B{'text': '(kq²/d)(4 + √2)', 'label': 'B'}
C{'text': '(kq²/d)(4 + 2/√2)', 'label': 'C'}
D{'text': '(kq²/d)(1 + 1/√2)', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': '(kq²/d)(4 + 2/√2)', 'label': 'C'}
1. Pairs: 4 sides at distance d (4 pairs) and 2 diagonals at distance d√2 (2 pairs).
2. Total PE = k q²[(4/d) + (2/(d√2))] = (k q²/d)(4 + 2/√2).
3. The work done from infinity equals this PE since the field at infinity does no work.
_Source: NCERT Class 12 Physics Part I, Ch 2 Example 2.4_
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