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Two capacitors of 4 µF and 6 µF are connected in parallel and charged by a 10 V battery. The total charge stored is
A{'text': '24 µC', 'label': 'A'}
B{'text': '60 µC', 'label': 'B'}
C{'text': '40 µC', 'label': 'C'}
D{'text': '100 µC', 'label': 'D'}
Answer & Solution
Correct answer: D. {'text': '100 µC', 'label': 'D'}
1. Parallel ⇒ Cₑ = 4 + 6 = 10 µF.
2. Q = Cₑ V = 10 × 10 = 100 µC.
3. Distractors come from using just one of the capacitors, or the series formula.
_Source: NCERT Class 12 Physics Part I, Ch 2 §2.14.2_
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